Vocal powerhouse Adam Lambert has been confirmed as the headliner of this year's Miami Beach Gay Pride event in Florida.

This year's festival will be the fifth annual Miami Beach Gay Pride Parade and Festival and a post on the event's official website explains that it will take place over the weekend of April 13-14.

The 'Trespassing' sensation will take the stage on Sunday night, April 14, and his performance is due to begin at approximately 8pm. Organisers of the festival have explained that his set will be held on the main stage in Lummus Park, which is "just off Ocean Drive, between 11th and 12th Street", and it will be free.

Miami Beach Gay Pride has also set up a page through which people can donate money in order to keep the festival as a free event and you can pledge funds here.

Lambert is a great spokesperson for the LGBT community and often speaks about being a gay idol while campaigning for equality. Late last year, the superstar performed at the second annual 'Home For The Holidays' concert in Manhattan, which was a charity event that raised money for homeless lesbian, gay, bisexual and transgender youths.

Watch Lambert perform a stunning rendition of 'Outlaws of Love' during a recent show here: